In the figure, F is the centre of a semicircle and FBCD is a rhombus. Given that ∠FDE = 25°, find
- ∠n
- ∠p
(a)
∠FDE
= ∠FED
= 25° (Isosceles triangle)
∠DFE
= 180° - 25° - 25°
= 130° (Angles sum of triangle)
∠n
= ∠DFE
= 130° (Corresponding angles)
(b)
∠p
= 180° - 130°
= 50° (Interior angles)
Answer(s): (a) 130°; (b) 50°