In the figure, N is the centre of a semicircle and NJKL is a rhombus. Given that ∠NLM = 27°, find
- ∠r
- ∠s
(a)
∠NLM
= ∠NML
= 27° (Isosceles triangle)
∠LNM
= 180° - 27° - 27°
= 126° (Angles sum of triangle)
∠r
= ∠LNM
= 126° (Corresponding angles)
(b)
∠s
= 180° - 126°
= 54° (Interior angles)
Answer(s): (a) 126°; (b) 54°