In the figure, H is the centre of a semicircle and HDEF is a rhombus. Given that ∠HFG = 31°, find
- ∠h
- ∠i
(a)
∠HFG
= ∠HGF
= 31° (Isosceles triangle)
∠FHG
= 180° - 31° - 31°
= 118° (Angles sum of triangle)
∠h
= ∠FHG
= 118° (Corresponding angles)
(b)
∠i
= 180° - 118°
= 62° (Interior angles)
Answer(s): (a) 118°; (b) 62°