In the figure, P is the centre of a semicircle and PKLM is a rhombus. Given that ∠PMN = 28°, find
- ∠i
- ∠j
(a)
∠PMN
= ∠PNM
= 28° (Isosceles triangle)
∠MPN
= 180° - 28° - 28°
= 124° (Angles sum of triangle)
∠i
= ∠MPN
= 124° (Corresponding angles)
(b)
∠j
= 180° - 124°
= 56° (Interior angles)
Answer(s): (a) 124°; (b) 56°