In the figure, N is the centre of a semicircle and NJKL is a rhombus. Given that ∠NLM = 28°, find
- ∠a
- ∠b
(a)
∠NLM
= ∠NML
= 28° (Isosceles triangle)
∠LNM
= 180° - 28° - 28°
= 124° (Angles sum of triangle)
∠a
= ∠LNM
= 124° (Corresponding angles)
(b)
∠b
= 180° - 124°
= 56° (Interior angles)
Answer(s): (a) 124°; (b) 56°