In the figure, K is the centre of a semicircle and KFGH is a rhombus. Given that ∠KHJ = 30°, find
- ∠d
- ∠e
(a)
∠KHJ
= ∠KJH
= 30° (Isosceles triangle)
∠HKJ
= 180° - 30° - 30°
= 120° (Angles sum of triangle)
∠d
= ∠HKJ
= 120° (Corresponding angles)
(b)
∠e
= 180° - 120°
= 60° (Interior angles)
Answer(s): (a) 120°; (b) 60°