In the figure, L is the centre of a semicircle and LGHJ is a rhombus. Given that ∠LJK = 27°, find
- ∠f
- ∠g
(a)
∠LJK
= ∠LKJ
= 27° (Isosceles triangle)
∠JLK
= 180° - 27° - 27°
= 126° (Angles sum of triangle)
∠f
= ∠JLK
= 126° (Corresponding angles)
(b)
∠g
= 180° - 126°
= 54° (Interior angles)
Answer(s): (a) 126°; (b) 54°