In the figure, T is the centre of a semicircle and TPQR is a rhombus. Given that ∠TRS = 29°, find
- ∠n
- ∠p
(a)
∠TRS
= ∠TSR
= 29° (Isosceles triangle)
∠RTS
= 180° - 29° - 29°
= 122° (Angles sum of triangle)
∠n
= ∠RTS
= 122° (Corresponding angles)
(b)
∠p
= 180° - 122°
= 58° (Interior angles)
Answer(s): (a) 122°; (b) 58°