In the figure, T is the centre of a semicircle and TPQR is a rhombus. Given that ∠TRS = 28°, find
- ∠c
- ∠d
(a)
∠TRS
= ∠TSR
= 28° (Isosceles triangle)
∠RTS
= 180° - 28° - 28°
= 124° (Angles sum of triangle)
∠c
= ∠RTS
= 124° (Corresponding angles)
(b)
∠d
= 180° - 124°
= 56° (Interior angles)
Answer(s): (a) 124°; (b) 56°