In the figure, F is the centre of a semicircle and FBCD is a rhombus. Given that ∠FDE = 31°, find
- ∠w
- ∠x
(a)
∠FDE
= ∠FED
= 31° (Isosceles triangle)
∠DFE
= 180° - 31° - 31°
= 118° (Angles sum of triangle)
∠w
= ∠DFE
= 118° (Corresponding angles)
(b)
∠x
= 180° - 118°
= 62° (Interior angles)
Answer(s): (a) 118°; (b) 62°