In the figure, N is the centre of a semicircle and NJKL is a rhombus. Given that ∠NLM = 31°, find
- ∠n
- ∠p
(a)
∠NLM
= ∠NML
= 31° (Isosceles triangle)
∠LNM
= 180° - 31° - 31°
= 118° (Angles sum of triangle)
∠n
= ∠LNM
= 118° (Corresponding angles)
(b)
∠p
= 180° - 118°
= 62° (Interior angles)
Answer(s): (a) 118°; (b) 62°