In the figure, S is the centre of a semicircle and SNPQ is a rhombus. Given that ∠SQR = 29°, find
- ∠y
- ∠z
(a)
∠SQR
= ∠SRQ
= 29° (Isosceles triangle)
∠QSR
= 180° - 29° - 29°
= 122° (Angles sum of triangle)
∠y
= ∠QSR
= 122° (Corresponding angles)
(b)
∠z
= 180° - 122°
= 58° (Interior angles)
Answer(s): (a) 122°; (b) 58°