In the figure, GHJK is a trapezium and GKLP is a rhombus. GK is parallel to HJ and KL = KM. PKJ and KNM are straight lines. ∠KGP = 47° and ∠NKP = 32°. Find
- ∠GKJ
- ∠KML
(a)
∠GKP
= (180° - 47°) ÷ 2
= 66.5° (Isosceles triangle)
∠GKJ
= 180° - 66.5°
= 113.5° (Angles on a straight line)
(b)
∠MKL
= 66.5° - 32°
= 34.5°
∠KML
= (180° - 34.5°) ÷ 2
= 72.75 ° (Isosceles triangle)
Answer(s): (a) 113.5°; (b) 72.75°