In the figure, NPQR is a trapezium and NRSV is a rhombus. NR is parallel to PQ and RS = RT. VRQ and RUT are straight lines. ∠RNV = 50° and ∠URV = 29°. Find
- ∠NRQ
- ∠RTS
(a)
∠NRV
= (180° - 50°) ÷ 2
= 65° (Isosceles triangle)
∠NRQ
= 180° - 65°
= 115° (Angles on a straight line)
(b)
∠TRS
= 65° - 29°
= 36°
∠RTS
= (180° - 36°) ÷ 2
= 72 ° (Isosceles triangle)
Answer(s): (a) 115°; (b) 72°