In the figure, PQRS is a trapezium and PSTW is a rhombus. PS is parallel to QR and ST = SU. WSR and SVU are straight lines. ∠SPW = 47° and ∠VSW = 25°. Find
- ∠PSR
- ∠SUT
(a)
∠PSW
= (180° - 47°) ÷ 2
= 66.5° (Isosceles triangle)
∠PSR
= 180° - 66.5°
= 113.5° (Angles on a straight line)
(b)
∠UST
= 66.5° - 25°
= 41.5°
∠SUT
= (180° - 41.5°) ÷ 2
= 69.25 ° (Isosceles triangle)
Answer(s): (a) 113.5°; (b) 69.25°