In the figure, STUV is a trapezium and SVWZ is a rhombus. SV is parallel to TU and VW = VX. ZVU and VYX are straight lines. ∠VSZ = 49° and ∠YVZ = 29°. Find
- ∠SVU
- ∠VXW
(a)
∠SVZ
= (180° - 49°) ÷ 2
= 65.5° (Isosceles triangle)
∠SVU
= 180° - 65.5°
= 114.5° (Angles on a straight line)
(b)
∠XVW
= 65.5° - 29°
= 36.5°
∠VXW
= (180° - 36.5°) ÷ 2
= 71.75 ° (Isosceles triangle)
Answer(s): (a) 114.5°; (b) 71.75°