In the figure, JKLM is a trapezium and JMNR is a rhombus. JM is parallel to KL and MN = MP. RML and MQP are straight lines. ∠MJR = 51° and ∠QMR = 34°. Find
- ∠JML
- ∠MPN
(a)
∠JMR
= (180° - 51°) ÷ 2
= 64.5° (Isosceles triangle)
∠JML
= 180° - 64.5°
= 115.5° (Angles on a straight line)
(b)
∠PMN
= 64.5° - 34°
= 30.5°
∠MPN
= (180° - 30.5°) ÷ 2
= 74.75 ° (Isosceles triangle)
Answer(s): (a) 115.5°; (b) 74.75°