In the figure, NPQR is a trapezium and NRSV is a rhombus. NR is parallel to PQ and RS = RT. VRQ and RUT are straight lines. ∠RNV = 40° and ∠URV = 27°. Find
- ∠NRQ
- ∠RTS
(a)
∠NRV
= (180° - 40°) ÷ 2
= 70° (Isosceles triangle)
∠NRQ
= 180° - 70°
= 110° (Angles on a straight line)
(b)
∠TRS
= 70° - 27°
= 43°
∠RTS
= (180° - 43°) ÷ 2
= 68.5 ° (Isosceles triangle)
Answer(s): (a) 110°; (b) 68.5°