In the figure, GHJK is a trapezium and GKLP is a rhombus. GK is parallel to HJ and KL = KM. PKJ and KNM are straight lines. ∠KGP = 52° and ∠NKP = 25°. Find
- ∠GKJ
- ∠KML
(a)
∠GKP
= (180° - 52°) ÷ 2
= 64° (Isosceles triangle)
∠GKJ
= 180° - 64°
= 116° (Angles on a straight line)
(b)
∠MKL
= 64° - 25°
= 39°
∠KML
= (180° - 39°) ÷ 2
= 70.5 ° (Isosceles triangle)
Answer(s): (a) 116°; (b) 70.5°