In the figure, PQRS is a trapezium and PSTW is a rhombus. PS is parallel to QR and ST = SU. WSR and SVU are straight lines. ∠SPW = 49° and ∠VSW = 26°. Find
- ∠PSR
- ∠SUT
(a)
∠PSW
= (180° - 49°) ÷ 2
= 65.5° (Isosceles triangle)
∠PSR
= 180° - 65.5°
= 114.5° (Angles on a straight line)
(b)
∠UST
= 65.5° - 26°
= 39.5°
∠SUT
= (180° - 39.5°) ÷ 2
= 70.25 ° (Isosceles triangle)
Answer(s): (a) 114.5°; (b) 70.25°