In the figure, PQRS is a trapezium and PSTW is a rhombus. PS is parallel to QR and ST = SU. WSR and SVU are straight lines. ∠SPW = 50° and ∠VSW = 34°. Find
- ∠PSR
- ∠SUT
(a)
∠PSW
= (180° - 50°) ÷ 2
= 65° (Isosceles triangle)
∠PSR
= 180° - 65°
= 115° (Angles on a straight line)
(b)
∠UST
= 65° - 34°
= 31°
∠SUT
= (180° - 31°) ÷ 2
= 74.5 ° (Isosceles triangle)
Answer(s): (a) 115°; (b) 74.5°