In the figure, GHJK is a trapezium and GKLP is a rhombus. GK is parallel to HJ and KL = KM. PKJ and KNM are straight lines. ∠KGP = 49° and ∠NKP = 35°. Find
- ∠GKJ
- ∠KML
(a)
∠GKP
= (180° - 49°) ÷ 2
= 65.5° (Isosceles triangle)
∠GKJ
= 180° - 65.5°
= 114.5° (Angles on a straight line)
(b)
∠MKL
= 65.5° - 35°
= 30.5°
∠KML
= (180° - 30.5°) ÷ 2
= 74.75 ° (Isosceles triangle)
Answer(s): (a) 114.5°; (b) 74.75°