In the figure, STUV is a trapezium and SVWZ is a rhombus. SV is parallel to TU and VW = VX. ZVU and VYX are straight lines. ∠VSZ = 41° and ∠YVZ = 27°. Find
- ∠SVU
- ∠VXW
(a)
∠SVZ
= (180° - 41°) ÷ 2
= 69.5° (Isosceles triangle)
∠SVU
= 180° - 69.5°
= 110.5° (Angles on a straight line)
(b)
∠XVW
= 69.5° - 27°
= 42.5°
∠VXW
= (180° - 42.5°) ÷ 2
= 68.75 ° (Isosceles triangle)
Answer(s): (a) 110.5°; (b) 68.75°