In the figure, GHJK is a trapezium and GKLP is a rhombus. GK is parallel to HJ and KL = KM. PKJ and KNM are straight lines. ∠KGP = 40° and ∠NKP = 29°. Find
- ∠GKJ
- ∠KML
(a)
∠GKP
= (180° - 40°) ÷ 2
= 70° (Isosceles triangle)
∠GKJ
= 180° - 70°
= 110° (Angles on a straight line)
(b)
∠MKL
= 70° - 29°
= 41°
∠KML
= (180° - 41°) ÷ 2
= 69.5 ° (Isosceles triangle)
Answer(s): (a) 110°; (b) 69.5°