In the figure, PQRS is a trapezium and PSTW is a rhombus. PS is parallel to QR and ST = SU. WSR and SVU are straight lines. ∠SPW = 43° and ∠VSW = 26°. Find
- ∠PSR
- ∠SUT
(a)
∠PSW
= (180° - 43°) ÷ 2
= 68.5° (Isosceles triangle)
∠PSR
= 180° - 68.5°
= 111.5° (Angles on a straight line)
(b)
∠UST
= 68.5° - 26°
= 42.5°
∠SUT
= (180° - 42.5°) ÷ 2
= 68.75 ° (Isosceles triangle)
Answer(s): (a) 111.5°; (b) 68.75°