In the figure, GHJK is a trapezium and GKLP is a rhombus. GK is parallel to HJ and KL = KM. PKJ and KNM are straight lines. ∠KGP = 46° and ∠NKP = 33°. Find
- ∠GKJ
- ∠KML
(a)
∠GKP
= (180° - 46°) ÷ 2
= 67° (Isosceles triangle)
∠GKJ
= 180° - 67°
= 113° (Angles on a straight line)
(b)
∠MKL
= 67° - 33°
= 34°
∠KML
= (180° - 34°) ÷ 2
= 73 ° (Isosceles triangle)
Answer(s): (a) 113°; (b) 73°