In the figure, BCDE is a trapezium and BEFJ is a rhombus. BE is parallel to CD and EF = EG. JED and EHG are straight lines. ∠EBJ = 44° and ∠HEJ = 34°. Find
- ∠BED
- ∠EGF
(a)
∠BEJ
= (180° - 44°) ÷ 2
= 68° (Isosceles triangle)
∠BED
= 180° - 68°
= 112° (Angles on a straight line)
(b)
∠GEF
= 68° - 34°
= 34°
∠EGF
= (180° - 34°) ÷ 2
= 73 ° (Isosceles triangle)
Answer(s): (a) 112°; (b) 73°