MNPQ is a rhombus, JKQ and NKP are straight lines. If NK = KQ, ∠KQP = 15° and ∠LNP = 30°, find
- ∠KPQ
- ∠LJK
(a)
∠KPQ
= 83° - 15°
= 68° (Exterior angle of a triangle)
(b)
∠NJK
= 83° - 30°
= 53° (Exterior angle of a triangle)
∠LJK
= 180° - 53°
= 127° (Angles on a straight line)
Answer(s): (a) 68°; (b) 127°