JKLM is a rhombus, FGM and KGL are straight lines. If KG = GM, ∠GML = 20° and ∠HKL = 35°, find
- ∠GLM
- ∠HFG
(a)
∠GLM
= 85° - 20°
= 65° (Exterior angle of a triangle)
(b)
∠KFG
= 85° - 35°
= 50° (Exterior angle of a triangle)
∠HFG
= 180° - 50°
= 130° (Angles on a straight line)
Answer(s): (a) 65°; (b) 130°