HJKL is a rhombus, EFL and JFK are straight lines. If JF = FL, ∠FLK = 18° and ∠GJK = 31°, find
- ∠FKL
- ∠GEF
(a)
∠FKL
= 87° - 18°
= 69° (Exterior angle of a triangle)
(b)
∠JEF
= 87° - 31°
= 56° (Exterior angle of a triangle)
∠GEF
= 180° - 56°
= 124° (Angles on a straight line)
Answer(s): (a) 69°; (b) 124°