MNPQ is a rhombus, JKQ and NKP are straight lines. If NK = KQ, ∠KQP = 20° and ∠LNP = 32°, find
- ∠KPQ
- ∠LJK
(a)
∠KPQ
= 84° - 20°
= 64° (Exterior angle of a triangle)
(b)
∠NJK
= 84° - 32°
= 52° (Exterior angle of a triangle)
∠LJK
= 180° - 52°
= 128° (Angles on a straight line)
Answer(s): (a) 64°; (b) 128°