FGHJ is a rhombus, CDJ and GDH are straight lines. If GD = DJ, ∠DJH = 17° and ∠EGH = 30°, find
- ∠DHJ
- ∠ECD
(a)
∠DHJ
= 86° - 17°
= 69° (Exterior angle of a triangle)
(b)
∠GCD
= 86° - 30°
= 56° (Exterior angle of a triangle)
∠ECD
= 180° - 56°
= 124° (Angles on a straight line)
Answer(s): (a) 69°; (b) 124°