LMNP is a rhombus, HJP and MJN are straight lines. If MJ = JP, ∠JPN = 15° and ∠KMN = 26°, find
- ∠JNP
- ∠KHJ
(a)
∠JNP
= 83° - 15°
= 68° (Exterior angle of a triangle)
(b)
∠MHJ
= 83° - 26°
= 57° (Exterior angle of a triangle)
∠KHJ
= 180° - 57°
= 123° (Angles on a straight line)
Answer(s): (a) 68°; (b) 123°