WXYZ is a rhombus, TUZ and XUY are straight lines. If XU = UZ, ∠UZY = 17° and ∠VXY = 28°, find
- ∠UYZ
- ∠VTU
(a)
∠UYZ
= 84° - 17°
= 67° (Exterior angle of a triangle)
(b)
∠XTU
= 84° - 28°
= 56° (Exterior angle of a triangle)
∠VTU
= 180° - 56°
= 124° (Angles on a straight line)
Answer(s): (a) 67°; (b) 124°