JKLM is a rhombus, FGM and KGL are straight lines. If KG = GM, ∠GML = 19° and ∠HKL = 34°, find
- ∠GLM
- ∠HFG
(a)
∠GLM
= 85° - 19°
= 66° (Exterior angle of a triangle)
(b)
∠KFG
= 85° - 34°
= 51° (Exterior angle of a triangle)
∠HFG
= 180° - 51°
= 129° (Angles on a straight line)
Answer(s): (a) 66°; (b) 129°