KLMN is a rhombus, GHN and LHM are straight lines. If LH = HN, ∠HNM = 19° and ∠JLM = 26°, find
- ∠HMN
- ∠JGH
(a)
∠HMN
= 87° - 19°
= 68° (Exterior angle of a triangle)
(b)
∠LGH
= 87° - 26°
= 61° (Exterior angle of a triangle)
∠JGH
= 180° - 61°
= 119° (Angles on a straight line)
Answer(s): (a) 68°; (b) 119°