GHJK is a rhombus, DEK and HEJ are straight lines. If HE = EK, ∠EKJ = 21° and ∠FHJ = 26°, find
- ∠EJK
- ∠FDE
(a)
∠EJK
= 88° - 21°
= 67° (Exterior angle of a triangle)
(b)
∠HDE
= 88° - 26°
= 62° (Exterior angle of a triangle)
∠FDE
= 180° - 62°
= 118° (Angles on a straight line)
Answer(s): (a) 67°; (b) 118°