FGHJ is a rhombus, CDJ and GDH are straight lines. If GD = DJ, ∠DJH = 15° and ∠EGH = 36°, find
- ∠DHJ
- ∠ECD
(a)
∠DHJ
= 84° - 15°
= 69° (Exterior angle of a triangle)
(b)
∠GCD
= 84° - 36°
= 48° (Exterior angle of a triangle)
∠ECD
= 180° - 48°
= 132° (Angles on a straight line)
Answer(s): (a) 69°; (b) 132°