KLMN is a rhombus, GHN and LHM are straight lines. If LH = HN, ∠HNM = 15° and ∠JLM = 29°, find
- ∠HMN
- ∠JGH
(a)
∠HMN
= 86° - 15°
= 71° (Exterior angle of a triangle)
(b)
∠LGH
= 86° - 29°
= 57° (Exterior angle of a triangle)
∠JGH
= 180° - 57°
= 123° (Angles on a straight line)
Answer(s): (a) 71°; (b) 123°