TUVW is a rhombus, QRW and URV are straight lines. If UR = RW, ∠RWV = 15° and ∠SUV = 36°, find
- ∠RVW
- ∠SQR
(a)
∠RVW
= 87° - 15°
= 72° (Exterior angle of a triangle)
(b)
∠UQR
= 87° - 36°
= 51° (Exterior angle of a triangle)
∠SQR
= 180° - 51°
= 129° (Angles on a straight line)
Answer(s): (a) 72°; (b) 129°