LMNP is a rhombus, HJP and MJN are straight lines. If MJ = JP, ∠JPN = 16° and ∠KMN = 27°, find
- ∠JNP
- ∠KHJ
(a)
∠JNP
= 87° - 16°
= 71° (Exterior angle of a triangle)
(b)
∠MHJ
= 87° - 27°
= 60° (Exterior angle of a triangle)
∠KHJ
= 180° - 60°
= 120° (Angles on a straight line)
Answer(s): (a) 71°; (b) 120°