JKLM is a rhombus, FGM and KGL are straight lines. If KG = GM, ∠GML = 18° and ∠HKL = 26°, find
- ∠GLM
- ∠HFG
(a)
∠GLM
= 87° - 18°
= 69° (Exterior angle of a triangle)
(b)
∠KFG
= 87° - 26°
= 61° (Exterior angle of a triangle)
∠HFG
= 180° - 61°
= 119° (Angles on a straight line)
Answer(s): (a) 69°; (b) 119°