TUVW is a rhombus, QRW and URV are straight lines. If UR = RW, ∠RWV = 16° and ∠SUV = 31°, find
- ∠RVW
- ∠SQR
(a)
∠RVW
= 86° - 16°
= 70° (Exterior angle of a triangle)
(b)
∠UQR
= 86° - 31°
= 55° (Exterior angle of a triangle)
∠SQR
= 180° - 55°
= 125° (Angles on a straight line)
Answer(s): (a) 70°; (b) 125°