KLMN is a rhombus, GHN and LHM are straight lines. If LH = HN, ∠HNM = 19° and ∠JLM = 35°, find
- ∠HMN
- ∠JGH
(a)
∠HMN
= 82° - 19°
= 63° (Exterior angle of a triangle)
(b)
∠LGH
= 82° - 35°
= 47° (Exterior angle of a triangle)
∠JGH
= 180° - 47°
= 133° (Angles on a straight line)
Answer(s): (a) 63°; (b) 133°