DEFG is a rhombus, ABG and EBF are straight lines. If EB = BG, ∠BGF = 20° and ∠CEF = 34°, find
- ∠BFG
- ∠CAB
(a)
∠BFG
= 81° - 20°
= 61° (Exterior angle of a triangle)
(b)
∠EAB
= 81° - 34°
= 47° (Exterior angle of a triangle)
∠CAB
= 180° - 47°
= 133° (Angles on a straight line)
Answer(s): (a) 61°; (b) 133°