HJKL is a rhombus, EFL and JFK are straight lines. If JF = FL, ∠FLK = 18° and ∠GJK = 29°, find
- ∠FKL
- ∠GEF
(a)
∠FKL
= 82° - 18°
= 64° (Exterior angle of a triangle)
(b)
∠JEF
= 82° - 29°
= 53° (Exterior angle of a triangle)
∠GEF
= 180° - 53°
= 127° (Angles on a straight line)
Answer(s): (a) 64°; (b) 127°