LMNP is a rhombus, HJP and MJN are straight lines. If MJ = JP, ∠JPN = 19° and ∠KMN = 30°, find
- ∠JNP
- ∠KHJ
(a)
∠JNP
= 86° - 19°
= 67° (Exterior angle of a triangle)
(b)
∠MHJ
= 86° - 30°
= 56° (Exterior angle of a triangle)
∠KHJ
= 180° - 56°
= 124° (Angles on a straight line)
Answer(s): (a) 67°; (b) 124°