FGHJ is a rhombus, CDJ and GDH are straight lines. If GD = DJ, ∠DJH = 19° and ∠EGH = 35°, find
- ∠DHJ
- ∠ECD
(a)
∠DHJ
= 87° - 19°
= 68° (Exterior angle of a triangle)
(b)
∠GCD
= 87° - 35°
= 52° (Exterior angle of a triangle)
∠ECD
= 180° - 52°
= 128° (Angles on a straight line)
Answer(s): (a) 68°; (b) 128°