NPQR is a rhombus, KLR and PLQ are straight lines. If PL = LR, ∠LRQ = 15° and ∠MPQ = 28°, find
- ∠LQR
- ∠MKL
(a)
∠LQR
= 86° - 15°
= 71° (Exterior angle of a triangle)
(b)
∠PKL
= 86° - 28°
= 58° (Exterior angle of a triangle)
∠MKL
= 180° - 58°
= 122° (Angles on a straight line)
Answer(s): (a) 71°; (b) 122°