WXYZ is a rhombus, TUZ and XUY are straight lines. If XU = UZ, ∠UZY = 19° and ∠VXY = 26°, find
- ∠UYZ
- ∠VTU
(a)
∠UYZ
= 87° - 19°
= 68° (Exterior angle of a triangle)
(b)
∠XTU
= 87° - 26°
= 61° (Exterior angle of a triangle)
∠VTU
= 180° - 61°
= 119° (Angles on a straight line)
Answer(s): (a) 68°; (b) 119°